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Team PC3-12800 Xtreem LV 4GB Dual-Channel Memory Kit - Test System Setup and wPrime


By: | DDR-3 Memory in RAM | Posted: Dec 15, 2009 10:04 am
TweakTown Rating: 90%Manufacturer: Team Group Inc

Test System Setup

 

Processor(s): Intel Core i7 920 @ 3.8GHz (190MHz x 20)
Cooling: Noctua NH-U12P (Supplied by Noctua)
Motherboard(s): ASROCK P55 Deluxe (Supplied by ASROCK)
Video Card: Gigabyte GTX 285 896MB (Supplied by GIGABYTE)
Hard Disk(s): Western Digital 300GB Velicorapter (Supplied by Western Digital)
Operating System: Windows 7
Drivers: Forceware 191.07

 


For our comparison today we'll have the Team modules running in the three different setups we achieved. The first is the stock timings; this is 1600MHz DDR 6-7-6-18-2T. The second is the same speed and timings except the command rate is now set to 1, making them 6-7-6-18-1T. Finally, we'll see how the modules performed at 9-9-9-18-2T at 2000MHz which was our overclocked speed.

 

Just for good measure, we've included the A-DATA X-Series modules which run at 2000MHz 9-9-9-24-1T and the G.Skill RipJaws which run at 2000MHz DDR as well, except with 9-9-9-27-2T timings.

 

Let's get started!

 


Important Note: When modules are overclocked we adjust the BCLK which not only lets us fine tune the MHz out of a module, but in turn increases the overall CPU clock speed. While we always make the effort to include the BCLK and CPU Speed in our graphs, please just make sure that you make note of these when looking at the results. In some tests that don't purely test the memory speed, the extra MHz on offer from the CPU can increase the result. Of course, it's worth noting that having faster memory also gives you the ability to run your CPU at a higher speed.

 


wPrime

 

Version and / or Patch Used: 1.62
Developer Homepage: http://www.wprime.net/
Product Homepage: http://www.wprime.net/

 


 

wPrime uses a recursive call of Newton's method for estimating functions, with f(x)=x2-k, where k is the number we're sqrting, until Sgn(f(x)/f'(x)) does not equal that of the previous iteration, starting with an estimation of k/2. It then uses an iterative calling of the estimation method a set amount of times to increase the accuracy of the results. It then confirms that n(k)2=k to ensure the calculation was correct. It repeats this for all numbers from 1 to the requested maximum.

 

content/3/0/3065_20.png

 

Across the board we can see there isn't a whole lot of time difference between all the setups.

 

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